Case 3 when a is a number, b is an even number, c is a number
assigned to a = 2m + 1, b = 2n, c = 2k + 1 when m, n, k, a member of the I +
is that a2 +. B2 = C2
4m2 + 4m + 1 + 4n2 = 4k2 + 4k + 1
K2 + K-m2-M-N2 = 0
(km) (K + M + 1) = N2
because n is a member of the I + so, n =
value selection. k and m a n a member of the I +
K = 2, M = 1; = 2 is a member of I +
as k = 2 and m = 1, so a = 2 (1) + 1 = 3 c = 2 (2) +. 1 = 5
= B = 4
second lead by either a, b, c are a = 6, b = 8, c = 10
, for example a triangle with the legs 6, 8 and 10 of the hypotenuse.
การแปล กรุณารอสักครู่..