Find n (E) before the same. The event that we are interested in is the number of points issued not less than 3, 4, 5, 6, 3, n
4, so there is an event (E) = 4
n (S) is the number of all results that may occur from dice. 1 ball 1 time
Therefore, n (S) = 6.6 P
is an event (E) = frac{n (E)} {n (S)} = 2 frac{4}{6} = 3 frac{2}{3}/
or the probability or likelihood that the Tao is the point of not less than 3: 2/3.
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