Axiom axiom 5 hack set (Subset Axiom). Mentioned as follows: For any set B set C which will be in accordance with condition x B x C, and is a member in writing as a symbol, as follows: c B x [ x B x C ] This axiom is to accept that there is any set B of a set C hack. Set B of C corresponds to hack the meaning of hack we've set and defined as the study of the definition as follows:Definition 4 hack set (Subset) Let A and B be sets B that it is called A member of sets every hack in set B are members in A set. Use symbols instead of text B A B is a hack of A frameset. Definition 4 cause of understanding that if one of the members of set B, it is not a member of A known hack of A set B is not. Use symbols instead of text B B A , not a hack of A frameset.Definition 5 hack (Proper Subset) sets Let A and B be sets Whether A call is a genuine set of choppers, B when A is a set, and A hack that is not equal to B. Call A set B of the hack is not a hack that does not set arbitrary set genuine hack (Improper Subset). Therefore, A set of sets, not genuine hack is available, and A selection of preset sets itself.Note: 1. this symbol is used in a phrase instead of set hack which does not specify clearly whether it is genuine or not set, hack. But we'll set that as a specific example, we hack genuine that is A specific set of genuine hack B B and A symbol representing A B. 2. for A hack that is set of may call B B that is super (Super Set) of A set. Example 5, W = {0, 1, 2, 3, ...,} Sets the number of W is called nature Center (Whole Number). We use a frameset to create sets of axioms, chop a couple of sets and create a number of prime numbers (Prime Number). As follows: B = {x is an even number x/W .} D = {x/x is the number of unique W .} 6 sample, S = {a, b, c, d, e}. We can create A frameset as a member in only 3 S b, c, a, is. Therefore, A = {a, b, c}. A S. Created by P P members to set is the set of sets S and every hack hack of the set S must have only a single member. ได้ P = { { a } , { b } , { c } , { d } , { e } }
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