We first discuss the effect of the absorptance, but assume that the recombination is purely radiative. For a solar cell, the absorbed photon current and with it<br>the short-circuit current is proportional to the absorptance, but this absorptance<br>a(ℏω) has to be counted only for a layer from which the minority carriers are<br>able to reach the contacts without recombining. The thickness of this layer is<br>equal to their diffusion length. For an LED, according to Equation 3.102, the<br>emitted photon current is also proportional to the absorptance and again this<br>absorptance is counted for a layer that is filled by minority carriers, when they<br>are injected through their selective contact. The thickness of this layer is equal to<br>the diffusion length. Although, the photon current, either absorbed or emitted,<br>is directly proportional to a(ℏω) for both devices, an absorptance a(ℏω) < 1<br>affects solar cells and LEDs differently. For a solar cell, nonabsorbed photons<br>are lost and result in a proportionate loss of the short-circuit current and of<br>the efficiency. For an LED, a(ℏω) < 1 means that less photons are emitted than<br>would be possible for the given voltage, but the charge current is accordingly<br>smaller, since only the electron–hole pairs that recombine have to be replenished<br>by the charge current. There is no direct loss involved. The photon current can<br>be raised to the ideal value expected for a(ℏω) = 1 by supplying a little more<br>energy, by raising the voltage in Equation 3.102 by an amount of kT/e ln(1/a).<br>So, if for an organic absorber/emitter, a(ℏω) = 0.01, a solar cell would have an<br>efficiency that is roughly smaller by a factor of 100 than the ideal efficiency and is<br>unacceptably small, whereas for a LED, the small absorptance of this material is<br>fully compensated by an additional voltage of only 120 mV.
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