5. ให้ A และ B เป็นเหตุการณ์บนปริภู

5. ให้ A และ B เป็นเหตุการณ์บนปริภูมิตัวอย่าง S กำหนดให้ P(A) = 0.4 และ P(B) = 0.5 จงหา P(AÈB) , P(A – B) และ P(A¢ÇB) ถ้า
​​ก. A และ B เป็นเหตุการณ์ไม่เกิดร่วมกัน
​​ข. A และ B เป็นเหตุการณ์ที่เป็นอิสระต่อกัน
ตอบ ก. ถ้า A และ B เป็นเหตุการณ์ไม่เกิดร่วมกัน แสดงว่า = 0
P(AÈB) = P(A)+P(B)-
​ = 0.4+0.5 -0 = 0.9
​ P(A-B) = P(A) - = 0.4-0 = 0.4
​ = P(B) - = 0.5
ข. ถ้า A และ B เป็นเหตุการณ์ที่เป็นอิสระต่อกัน แสดงว่า = P(A)P(B)
P(AÈB) = P(A)+P(B)- = P(A)+P(B)- P(A)P(B)
​ P(A-B) = P(A) - = P(A) – P(A)P(B)
​ = P(B) - = P(B) – P(A)P(B)

ผลลัพธ์ (อังกฤษ) 1:

5. A and B is the event on the spatial sample S, P (A) = P (B) = 0.4 and 0.5 shall find P (AÈB), P (A – B) and P (ÇB A¢)
g A and B is the event does not occur together
ข. A and B are independent events
. Answered by g.5. A and B is the event on the spatial sample S, P (A) = P (B) = 0.4 and 0.5 shall find P (AÈB), P (A – B) and P (ÇB A¢)
g A and B is the event does not occur together
ข. A and B are independent events
. Answered by g.5. A and B is the event on the spatial sample S, P (A) = P (B) = 0.4 and 0.5 shall find P (AÈB), P (A – B) and P (ÇB A¢)
g A and B is the event does not occur together
ข. A and B are independent events
. Answered by g.= P(B) - = P(B) – P(A)P(B) If A and B are the event does not occur together shows that = 0
P (AÈB) = P (A) P (B) = 0.5 0.4-0
-
P = 0.9 (A-B) = P (A) = 0-0.4 0.4 = P
=-(B)-0.5 =
ข. If A and B are independent events, show that = P (A) P (B)
P (AÈB) = P (A) P (B) = P (A)-(B) P-P (A) P (B)
P (A-B) = P (A) = P (A) – P (A) P (B)
.

ผลลัพธ์ (อังกฤษ) 2:

. 5 A and B are incident on the sample space S defined as P (A) = 0.4 and P (B) = 0.5, find P (AÈB), P (A - B) and P (A ¢ ÇB) if.
A. A and B are not mutually exclusive events.
above. A and B are independent events.
answer A. If A and B are not mutually exclusive events that = 0.
P (Aeb) = P (A) + P (B) -.
= 0.4 +0.5 = -0 0.9
P (AB) = P (A) - = .4-0 = 0.4.
= P (B) - = 0.5.
b., if A and B are independent events, show that = P (A) P (B. )
P (Aeb) = P (A) + P (B) - = P (A) + P (B) - P (A) P (B).
P (AB) = P (A) - = P (A. ) - P (A) P (B).
= P (B) - = P (B) - P (A) P (B).

ผลลัพธ์ (อังกฤษ) 3:

5. A B and is incident on the sample space S destined to P (A) = 0.4 P (and B) = 0.5 seek P (A È B), P (A - B) and P (A by Ç B) if
en G. A B events is not and mutually
en B. A B events and independent
answer.5. A B and is incident on the sample space S destined to P (A) = 0.4 P (and B) = 0.5 seek P (A È B), P (A - B) and P (A by Ç B) if
en G. A B events is not and mutually
en B. A B events and independent
answer.5. A B and is incident on the sample space S destined to P (A) = 0.4 P (and B) = 0.5 seek P (A È B), P (A - B) and P (A by Ç B) if
en G. A B events is not and mutually
en B. A B events and independent
answer.If A B event and not occur together. So = 0
P (A È B) = P (A) P (B) -
a = 0.4 0.5 - 0 = 0.9
the P (A-B) = P (A) - = 0.4-0. 0.4
a = P (B) - = 0.5
B. if and A B is an independent means = P (A) P (B)
P (A È B) = P (A) P (B) - = P (A) P (B). P (A) P (B)
the P (A-B) = P (A) - = P (A) - P (A) P (B)
.A = P (B) - = P (B) - P (A) P (B).