Given a circle radius R n side polygon-shaped attachment angle equal to that of an equilateral triangle "n-shape corner only equals 〗 〖 nR ^ 2. Θ by θ, tan, 2 2 π/n 2 π, which divided into n equal parts.
Make a circle of radius R attached in an n-sided polygon as far as the areas that are of an n-sided polygon corner as far as nR 〖〗 ^ 2 tanθ by 2θ equal to 2π / n 2π is divided into n equal parts. more
The circle radius R attached in the form n square sides equal angles, is that the area of a square aspect as n equiangular equals 〖 nR 〗 ^ 2 Tan θ. The 2 θ was 2 π / N which are divided into 2 π N equal parts.