The event was the red candy both tablets (R1 R2),,, (R1 R3), (,), (R1 R4, R2 R3), (,), (R2 R4, R3 R4)
, which has 6, or 6 event. So n (E) = 6
so the probability of picking a red candy both tablets is
P (E) = - {n frac (E)} {n (S)} = - {} {frac 6 15} = - {2 5 frac} {}
.
2 / 5.
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