5. find the values of a function (' how creative). A simple function to find the value of From the known and said, "if (a, b) f and b is called the domain of the function f is equal to a" this message is written instead of yo f (a) = b. Therefore, To find the domain of the function f is equal to the value of a is the coordinates of the top pair in f with the first coordinate is a, which is found by substituting x = a value into the equation of the function f has a value of function f which equals a domain as required. Example 3 given f = {(x, y) R R y = 2x + 1 |} You shall find the values of f (ii), f (3), f (4), f (a), f (a + 1), and f (x + 1). How to make from the equation y = 2x + 1. Instead of x = 2, y = 2, it will have (2) + 1 = 5 = f (2) Instead of x = 3, y = 2, it will have (3) + 1 = 7 = f (3) Instead of x = 4, y = 2, it will have (4) + 1 = 9 = f (4) Replace x = y = 2 a shall be (a) + 1 = 2a + 1 = f (a). Replace x = y = a + 1 will be 2 (a + 1) + 1 = 2a + 3 = f (a + 1). Replace x = y = x + 1.2 (x + 1) + 1 = 2x + 3 = f (x + 1). G = {(x, y) R R |} is a function. Consider the equation When the substitution y = 1, x = ± 1, 2 up. Therefore, it is no function 1-1 g. 2. how the graph of the function f if the function's graph see see a straight line that is parallel to the x axis of the graph of f over some line wrapping for 1 point and f is not a function 1-1 (if the straight line parallel to the x axis of the graph of f cutting line no more than 1 point and f is a function, 1-1).
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